Mathematics
In the given figure, O is center of the circle and ∠COD is greater than ∠AOB, then :

AB > CD
AB < CD
AB = CD
AB + CD = AD
Related Questions
In the following figure, the line ABCD is perpendicular to PQ; where P and Q are the centers of the circles. Show that :

(i) AB = CD
(ii) AC = BD
In the given figure, arc APB = arc CQD, then :

AB = CD
AB > CD
AB < CD
none of the above
In a circle, O is its center and AB, CD are its two chords. If AB : CD = 3 : 2, then ratio between ∠AOB and ∠COD is :
1 : 1
3 : 2
2 : 5
3 : 5
In the given figure, O is the center of the circle and ABC is an equilateral triangle, then ∠AOB is equal to :

105°
90°
60°
120°