Mathematics
Related Questions
In the adjoining figure, we find :

BD = DC
BD < DC
BD > DC
AD = CD
In the given figure, AB = AC, then :

BD = BC
BD = CD
BD < CD
BD > CD
In the given figure, we find :

AB > AC
AC > AB
AB < BC
AC = AB
In a quadrilateral ABCD,
AB + BC + CD + DA > AC + BD
AB + BC + CD + DA < AC + BD
AB + BC + CD + DA = AC + BD
AB + BC < AC
