Mathematics
In triangle ABC; ∠A = 60°, ∠C = 40° and bisector of angle ABC meets side AC at point P. Show that BP = CP.
Related Questions
In the triangle ABC, BD bisects angle B and is perpendicular to AC. If the lengths of the sides of the triangle are expressed in terms of x and y as shown, find the values of x and y.
In triangle ABC; AB = AC and ∠A : ∠B = 8 : 5; find angle A.
In the given figure, AB ⊥ BE, EF ⊥ BE, AB = EF and BC = DE, then :
△ ABD ≅ △ EFC
△ ABD ≅ △ FEC
△ ABD ≅ △ ECF
△ ABD ≅ △ CEF
From the adjoining figure, we find :
OP = OR
OP = OQ
PQ = PR
PR ≠ PQ
