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An iron nail is added to each of the two test tubes ‘P’ and ‘Q’ containing aqueous copper (II) sulphate and aqueous silver nitrate respectively. Which of the following observation is correct?

options

  1. In test tube ‘P’ iron nail is coated with a blue coating and in test tube ‘Q’ there is no reaction.
  2. Iron nail is coated with a brown coating in test tube ‘P’ and silver coating in test tube ‘Q’.
  3. There is no reaction in either of the test tubes ‘P’ or ‘Q’.
  4. There is no reaction in test tube ‘P’ but a silver coating on iron nail is seen in test tube ‘Q’.

Chemical Reaction

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Answer

Iron nail is coated with a brown coating in test tube ‘P’ and silver coating in test tube ‘Q’.

Reason

In test tube ‘P’, the solution contains copper (II) sulphate (CuSO4) so when an iron nail is dipped into it, a displacement reaction occurs because iron (Fe) is more reactive than copper (Cu).
Iron displaces copper from copper sulphate, forming iron(II) sulphate (FeSO4) and brown copper metal, which gets deposited on the nail.
Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Thus, the nail becomes coated with brown copper.

In test tube ‘Q’, the solution contains silver nitrate (AgNO3). Again, iron is more reactive than silver (Ag), so it displaces silver from the solution, forming iron(II) nitrate (Fe(NO3)2) and depositing shiny silver metal on the nail.
Fe(s) + 2AgNO3(aq) → Fe(NO3)2(aq) + 2Ag(s)

Hence, in test tube ‘P’ the nail gets a brown coating of copper and in test tube ‘Q’ a silver coating is formed.

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