∜28 ÷ ∜7 is equal to : 1. √2 2. √4 3. ∜2 4. ∛2

Simplifying the expression : Hence, Option 1 is the correct option.

Mathematics

$\sqrt[4]{28} ÷ \sqrt[4]{7}$ is equal to :
$\sqrt{2}$
$\sqrt{4}$
$\sqrt[4]{2}$
$\sqrt[3]{2}$

Indices

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Answer

Simplifying the expression :

$\Rightarrow \sqrt[4]{28} ÷ \sqrt[4]{7} = \dfrac{\sqrt[4]{28}}{\sqrt[4]{7}} \\[1em] = \Big(\dfrac{28}{7}\Big)^{\dfrac{1}{4}} = (4)^{\dfrac{1}{4}} \\[1em] = (2)^{2 \times \dfrac{1}{4}} = (2)^{\dfrac{1}{2}} \\[1em] = \sqrt{2}.$

Hence, Option 1 is the correct option.

Answered By

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Mathematics

$\sqrt[4]{28} ÷ \sqrt[4]{7}$ is equal to :
$\sqrt{2}$
$\sqrt{4}$
$\sqrt[4]{2}$
$\sqrt[3]{2}$

Indices

Answer

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Mathematics

284÷74\sqrt[4]{28} ÷ \sqrt[4]{7}428​÷47​ is equal to :2\sqrt{2}2​4\sqrt{4}4​24\sqrt[4]{2}42​23\sqrt[3]{2}32​

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$\sqrt[4]{28} ÷ \sqrt[4]{7}$ is equal to :
$\sqrt{2}$
$\sqrt{4}$
$\sqrt[4]{2}$
$\sqrt[3]{2}$

$\Big(-\dfrac{2a^2}{b^3}\Big)^4$ is equal to :
$-\dfrac{16a^8}{b^{12}}$
$\dfrac{16a^8}{b^{12}}$
$\dfrac{2a^8}{b^{12}}$
$-\dfrac{2a^8}{b^{12}}$

$\Big(\dfrac{25}{9}\Big)^{-\dfrac{3}{2}}$ is equal to :
$\Big(\dfrac{5}{3}\Big)^3$
$\Big(\dfrac{5}{3}\Big)^2$
$\dfrac{27}{125}$
$\Big(\dfrac{3}{5}\Big)^{-2}$

$2 ÷ (243)^{-\dfrac{1}{5}}$ is equal to :
2 ÷ 3
$\dfrac{1}{6}$
12
6

$(0.01)^{-\dfrac{1}{2}}$ :
10
0.1
$(0.1)^{\frac{1}{2}}$
0.0001