The lengths of diagonals of a rhombus are 24 cm and 18 cm respectively, length of each side of the rhombus is :

1. 25 cm

2. 15 cm

3. 35 cm

4. 45 cm

The diagonals of a rhombus are 18 cm and 24 cm.

AC = 18 cm

Then, OA = OC = $\dfrac{18}{2}$ = 9 cm.

And, BD = 24 cm

Then, OB = OD = $\dfrac{24}{2}$ = 12 cm.

Since the diagonals of a rhombus bisect at 90°.

Applying pythagoras theorem in triangle AOB, we get :

⇒ AB² = OA² + OB²

⇒ AB² = (9)² + (12)²

⇒ AB² = 81 + 144

⇒ AB² = 225

⇒ AB = $\sqrt{225}$

⇒ AB = 15 cm.

Hence, option 2 is the correct option.