If the lines x – my + 3 = 0 and 2x + 3y – 7 = 0 are perpendicular to each other, then the value of m is: 1. 2. 3. 4.

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KnowledgeBoat · Accepted Answer

For two lines to be perpendicular, the product of their slopes must be -1. Line 1: x - my + 3 = 0 First, convert the equation x - my + 3 = 0 into the slope-intercept form, y = mx + c, to find its slope, m. Line 2: 2x + 3y - 7 = 0 First, convert the equation 2x + 3y - 7 = 0 into the slope-intercept form, y = mx + c, to find its slope, m. The product of slopes of perpendicular lines is equal to -1: Hence, option 2 is the correct option.

Mathematics

If the lines x – my + 3 = 0 and 2x + 3y – 7 = 0 are perpendicular to each other, then the value of m is: 1. 2. 3. 4.

Straight Line Eq

Related Questions

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:
x – 3y + 1 = 0
3x + y + 1 = 0
3x – y – 1 = 0
3x – y + 1 = 0

Mathematics

If the lines x – my + 3 = 0 and 2x + 3y – 7 = 0 are perpendicular to each other, then the value of m is: 1. 2. 3. 4.

Straight Line Eq

Related Questions

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:x – 3y + 1 = 03x + y + 1 = 03x – y – 1 = 03x – y + 1 = 0

The equation of the straight line passing through the point (1, 2) and parallel to the line y = 3x + 1, is:
x – 3y + 1 = 0
3x + y + 1 = 0
3x – y – 1 = 0
3x – y + 1 = 0