If log10 x = p and log10 y = q, show that xy = (10)p + q.
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Given,
⇒ log10 x = p and log10 y = q
⇒ x = 10p and y = 10q
⇒ x × y = 10p × 10q
⇒ xy = (10)p + q.
Hence, proved that xy = (10)p + q.
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Given log10 x = a, log10 y = b,
(i) Write down 10a + 1 in terms of x.
(ii) Write down 102b in terms of y.
(iii) If log10 P = 2a − b, express P in terms of x and y.