Mathematics
If log10 x = p and log10 y = q, show that xy = (10)p + q.
Logarithms
1 Like
Answer
Given,
⇒ log10 x = p and log10 y = q
⇒ x = 10p and y = 10q
⇒ x × y = 10p × 10q
⇒ xy = (10)p + q.
Hence, proved that xy = (10)p + q.
Answered By
2 Likes
Related Questions
By converting to exponential form, find the value of each of the following:
(i) log2 64
(ii) log8 32
(iii) log3
(iv) log0.5 (16)
(v) log2 (0.125)
(vi) log7 7
Find the value of x, when:
(i) log2 x = -2
(ii) logx 9 = 1
(iii) log9 243 = x
(iv) log3 x = 0
(v) (x − 1) = 2
(vi) log5 (x2 − 19) = 3
(vii) logx 64 =
(viii) log2 (x2 − 9) = 4
(ix) logx (0.008) = −3
Given log10 x = a, log10 y = b,
(i) Write down 10a + 1 in terms of x.
(ii) Write down 102b in terms of y.
(iii) If log10 P = 2a − b, express P in terms of x and y.
Evaluate the following without using log tables :
2 log 5 + log 8 − log 4