Chemistry
LPG has 60% propane and 40% butane: 10 litres of this mixture is burnt. Calculate the volume of carbon dioxide added to the atmosphere.
C3H8 + 5O2 ⟶ 3CO2 + 4H2O
2C4H10 + 13O2 ⟶ 8CO2 + 10H2O
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Answer
Given, 10 litres of this mixture contains 60% propane and 40% butane. Hence, propane is 6 litres and butane is 4 litres
1 Vol. C3H8 produces carbon dioxide = 3 Vol
So, 6 litres C3H8 will produce carbon dioxide = 3 x 6 = 18 litres
2 Vol. C4H10 produces carbon dioxide = 8 Vol
So, 4 litres C4H10 will produce carbon dioxide = x 4 = 16 litres
Hence, 34 (i.e., 18 + 16) litres of CO2 is produced.
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