A man is 28 years older than his son. After 10 years, he will be thrice as old as his son. Find their present ages.
Linear Eqns One Variable
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Question

A man is 28 years older than his son. After 10 years, he will be thrice as old as his son. Find their present ages.

KnowledgeBoat · Accepted Answer

Let the son's present age be x years. Then, the man's present age = (x + 28) years. After 10 years: Son's age = (x + 10) years. Man's age = (x + 28 + 10) years = (x + 38) years. According to the question, after 10 years, the man will be thrice as old as his son: x + 38 = 3(x + 10) ⇒ x + 38 = 3x + 30 ⇒ x - 3x = 30 - 38 [Transposing +38 to RHS and +3x to LHS] ⇒ -2x = -8 ⇒ x = ⇒ x = 4 Son's present age = x years = 4 years. Man's present age = (x + 28) years = (4 + 28) years = 32 years. Hence, the man's present age is 32 years and his son's age is 4 years.

Mathematics

A man is 28 years older than his son. After 10 years, he will be thrice as old as his son. Find their present ages.

Linear Eqns One Variable

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