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Physics

The mechanical advantage of a machine is 5. How much load it can exert for the effort of 2 kgf?

Machines

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Answer

Given,

Mechanical advantage of the machine = 5

Effort = 2 kgf

As,

Mechanical Advantage=LoadEffort⇒Load=Mechanical Advantage ×Effort=5 ×2 kgf=10 kgf\text {Mechanical Advantage}=\dfrac{\text {Load}}{\text {Effort}}\\[1 em] \Rightarrow \text {Load} = \text {Mechanical Advantage} \ \times \text {Effort} = 5\ \times 2 \text { kgf} = 10\text { kgf}

Thus, load can exert 10 kgf force for the effort of 2 kgf.

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