The median of the data 2, 7, 9, 13, 20, 22, 24, 25, 27, 28, 35, 40, is :

1. 24

2. 23

3. 25

4. 27

The data is already arranged in the ascending order.

Number of observations, n = 12, which is even.

By formula,

$\Rightarrow \text{Median} = \dfrac{\left(\dfrac{n}{2}\right)^{\text{th}} \text{term} + \left(\dfrac{n}{2} + 1\right)^{\text{th}} \text{term}}{2} \\[1em] \Rightarrow \text{Median} = \dfrac{\left(\dfrac{12}{2}\right)^{\text{th}} \text{term} + \left(\dfrac{12}{2} + 1\right)^{\text{th}} \text{term}}{2} \\[1em] \Rightarrow \text{Median} = \dfrac{\text{6th term} + \text{7th term}}{2} \\[1em] \Rightarrow \text{Median} = \dfrac{\text{22} + \text{24}}{2} \\[1em] \Rightarrow \text{Median} = \dfrac{\text{46}}{2} \\[1em]$

∴ Median = 23.

Hence, option 2 is the correct option.