Mathematics

The mid-point of the line segment joining the points (-3, 2) and (7, 6) is:
(-2, -4)
(-2, 4)
(2, 4)
(4, 2)

Section Formula

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Answer

Let the mid-point be M(x, y).

The mid-point of the line segment joining the points (-3, 2) and (7, 6) is: Reflection, RSA Mathematics Solutions ICSE Class 10.

By mid-point formula,

(x, y) = $\Big(\dfrac{x$

Substituting values we get :

$\Rightarrow M(x, y) = \Big(\dfrac{-3 + 7}{2}, \dfrac{2 + 6}{2}\Big) \\[1em] \Rightarrow \Big(\dfrac{4}{2}, \dfrac{8}{2}\Big) \\[1em] \Rightarrow (2, 4).$

Hence, Option 3 is the correct option.

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Mathematics

The mid-point of the line segment joining the points (-3, 2) and (7, 6) is:
(-2, -4)
(-2, 4)
(2, 4)
(4, 2)

Section Formula

Answer

Related Questions

In the adjoining figure, P(5, -3) and Q(3, y) are the points of trisection of the line segment joining A(7, -2) and B(1, -5). Then, y equals :
-4
$\Big(\dfrac{-5}{2}\Big)$
2
4

If the point P(6, -3) lies on the line segment joining points A(4, 2) and B(8, 4), then:
AP = $\dfrac{3}{4}$ AB
AP = $\dfrac{1}{4}$ AB
PB = $\dfrac{1}{3}$ AB
AP = $\dfrac{1}{2}$ AB

If A(4, 2), B(6, 5) and C(1, 4) be the vertices of ΔABC and AD is a median, then the coordinates of D are:
$\Big(\dfrac{5}{2}, 3\Big)$
$\Big(5, \dfrac{7}{2}\Big)$
$\Big(\dfrac{7}{2}, \dfrac{9}{2}\Big)$
none of these

If (3, -6) is the mid-point of the line segment joining (0, 0) and (x, y), then the point (x, y) is:
(-3, 6)
(6, -6)
(6, -12)
$\Big(\dfrac{3}{2}, -3\Big)$

Mathematics

The mid-point of the line segment joining the points (-3, 2) and (7, 6) is:(-2, -4)(-2, 4)(2, 4)(4, 2)

Section Formula

Answer

Related Questions

In the adjoining figure, P(5, -3) and Q(3, y) are the points of trisection of the line segment joining A(7, -2) and B(1, -5). Then, y equals :-4(−52)\Big(\dfrac{-5}{2}\Big)(2−5​)24

If the point P(6, -3) lies on the line segment joining points A(4, 2) and B(8, 4), then:AP = 34\dfrac{3}{4}43​ ABAP = 14\dfrac{1}{4}41​ ABPB = 13\dfrac{1}{3}31​ ABAP = 12\dfrac{1}{2}21​ AB

If A(4, 2), B(6, 5) and C(1, 4) be the vertices of ΔABC and AD is a median, then the coordinates of D are:(52,3)\Big(\dfrac{5}{2}, 3\Big)(25​,3)(5,72)\Big(5, \dfrac{7}{2}\Big)(5,27​)(72,92)\Big(\dfrac{7}{2}, \dfrac{9}{2}\Big)(27​,29​)none of these

If (3, -6) is the mid-point of the line segment joining (0, 0) and (x, y), then the point (x, y) is:(-3, 6)(6, -6)(6, -12)(32,−3)\Big(\dfrac{3}{2}, -3\Big)(23​,−3)

The mid-point of the line segment joining the points (-3, 2) and (7, 6) is:
(-2, -4)
(-2, 4)
(2, 4)
(4, 2)

In the adjoining figure, P(5, -3) and Q(3, y) are the points of trisection of the line segment joining A(7, -2) and B(1, -5). Then, y equals :
-4
$\Big(\dfrac{-5}{2}\Big)$
2
4

If the point P(6, -3) lies on the line segment joining points A(4, 2) and B(8, 4), then:
AP = $\dfrac{3}{4}$ AB
AP = $\dfrac{1}{4}$ AB
PB = $\dfrac{1}{3}$ AB
AP = $\dfrac{1}{2}$ AB

If A(4, 2), B(6, 5) and C(1, 4) be the vertices of ΔABC and AD is a median, then the coordinates of D are:
$\Big(\dfrac{5}{2}, 3\Big)$
$\Big(5, \dfrac{7}{2}\Big)$
$\Big(\dfrac{7}{2}, \dfrac{9}{2}\Big)$
none of these

If (3, -6) is the mid-point of the line segment joining (0, 0) and (x, y), then the point (x, y) is:
(-3, 6)
(6, -6)
(6, -12)
$\Big(\dfrac{3}{2}, -3\Big)$