(3−32xy+75xy2−2116x2y)×(−21x2y2)=(3×(−21x2y2)−32xy×(−21x2y2)+75xy2×(−21x2y2)−2116x2y×(−21x2y2))=(−63x2y2−32×(−21)x1+2y1+2+75×(−21)x1+2y2+2−2116×(−21)x2+2y1+2)=−63x2y2−3−42x3y3+7−105x3y4+2116×(21)x4y3=−63x2y2+14x3y3−15x3y4+16x4y3
Hence, (3 - 32xy+75xy2−2116 x2y) x (- 21x2y2) = -63x2y2 + 14x3y3 - 15x3y4 + 16x4y3