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Mathematics

Multiply :

2x + 12\dfrac{1}{2} y and 2x - 12\dfrac{1}{2} y

Algebraic Expressions

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Answer

(2x+12y)×(2x12y)=2x×(2x12y)+12y×(2x12y)=(2x×2x2x×12y)+(12y×2x12y×12y)=(4x1+12xy2)+(2xy21×12×2y1+1)=(4x2xy)+(xy14y2)=4x2xy+xy14y2=4x2xy+xy14y2=4x214y2\Big(2x + \dfrac{1}{2}y\Big) \times \Big(2x - \dfrac{1}{2}y\Big)\\[1em] = 2x \times \Big(2x - \dfrac{1}{2}y\Big) + \dfrac{1}{2}y \times \Big(2x - \dfrac{1}{2}y\Big)\\[1em] =\Big(2x \times 2x - 2x \times \dfrac{1}{2}y\Big) + \Big(\dfrac{1}{2}y \times 2x - \dfrac{1}{2}y \times \dfrac{1}{2}y\Big)\\[1em] =\Big(4x^{1+1} - \dfrac{2xy}{2}\Big) + \Big(\dfrac{2xy}{2} - \dfrac{1 \times 1}{2 \times 2}y^{1+1}\Big)\\[1em] = (4x^2 - xy) + \Big(xy - \dfrac{1}{4}y^{2}\Big)\\[1em] = 4x^2 - xy + xy - \dfrac{1}{4}y^{2}\\[1em] = 4x^2 - \cancel{xy} + \cancel{xy} - \dfrac{1}{4}y^{2}\\[1em] = 4x^2 - \dfrac{1}{4}y^2

Hence, 2x + 12\dfrac{1}{2} y x 2x - 12\dfrac{1}{2} y = 4x2 - 14\dfrac{1}{4} y2

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