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Mathematics

Multiply :

2a3 - 3a2b and 12-\dfrac{1}{2} ab2

Algebraic Expressions

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Answer

(2a33a2b)×(12ab2)=[2a3×(12ab2)3a2b×(12ab2)]=1×22a3+1b2+1×32a2+1b1+2=22a4b2+32a3b3=a4b2+32a3b3(2a^3 - 3a^2b) \times \Big(-\dfrac{1}{2}ab^2\Big)\\[1em] = \Big[2a^3 \times (- \dfrac{1}{2}ab^2) - 3a^2b \times (- \dfrac{1}{2}ab^2)\Big]\\[1em] = - \dfrac{1 \times 2}{2}a^{3+1}b^2 + \dfrac{1 \times 3}{2}a^{2+1}b^{1+2}\\[1em] = - \dfrac{2}{2}a^4b^2 + \dfrac{3}{2}a^3b^3\\[1em] = - a^4b^2 + \dfrac{3}{2}a^3b^3\\[1em]

Hence, 2a3 - 3a2b x 12-\dfrac{1}{2} ab2 = -a4b2 + 32\dfrac{3}{2} a3b3

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