Multiply :
2a3 - 3a2b and −12-\dfrac{1}{2}−21 ab2
3 Likes
(2a3−3a2b)×(−12ab2)=[2a3×(−12ab2)−3a2b×(−12ab2)]=−1×22a3+1b2+1×32a2+1b1+2=−22a4b2+32a3b3=−a4b2+32a3b3(2a^3 - 3a^2b) \times \Big(-\dfrac{1}{2}ab^2\Big)\\[1em] = \Big[2a^3 \times (- \dfrac{1}{2}ab^2) - 3a^2b \times (- \dfrac{1}{2}ab^2)\Big]\\[1em] = - \dfrac{1 \times 2}{2}a^{3+1}b^2 + \dfrac{1 \times 3}{2}a^{2+1}b^{1+2}\\[1em] = - \dfrac{2}{2}a^4b^2 + \dfrac{3}{2}a^3b^3\\[1em] = - a^4b^2 + \dfrac{3}{2}a^3b^3\\[1em](2a3−3a2b)×(−21ab2)=[2a3×(−21ab2)−3a2b×(−21ab2)]=−21×2a3+1b2+21×3a2+1b1+2=−22a4b2+23a3b3=−a4b2+23a3b3
Hence, 2a3 - 3a2b x −12-\dfrac{1}{2}−21 ab2 = -a4b2 + 32\dfrac{3}{2}23 a3b3
Answered By
1 Like
- 32\dfrac{3}{2}23 x5y3 and 49\dfrac{4}{9}94 a2x3y
−23-\dfrac{2}{3}−32 a7b2 and −94-\dfrac{9}{4}−49 ab5
2x + 12\dfrac{1}{2}21 y and 2x - 12\dfrac{1}{2}21 y
5x2 - 8xy + 6y2 - 3 by - 3xy