Multiply :
- 32\dfrac{3}{2}23 x5y3 and 49\dfrac{4}{9}94 a2x3y
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−32x5y3×49a2x3y=−3×42×9a2x5+3y3+1=−1218a2x8y4=−23a2x8y4-\dfrac{3}{2}x^5y^3 \times \dfrac{4}{9}a^2x^3y\\[1em] = -\dfrac{3 \times 4}{2 \times 9}a^2x^{5+3}y^{3+1}\\[1em] = -\dfrac{12}{18}a^2x^8y^4\\[1em] = -\dfrac{2}{3}a^2x^8y^4\\[1em]−23x5y3×94a2x3y=−2×93×4a2x5+3y3+1=−1812a2x8y4=−32a2x8y4
Hence, - 32\dfrac{3}{2}23 x5 y3 x 49\dfrac{4}{9}94 a2x3y = - 23\dfrac{2}{3}32 a2x8y4
Answered By
abx, - 3a2x and 7b2x3
- 3bx, - 5xy and - 7b3y2
−23-\dfrac{2}{3}−32 a7b2 and −94-\dfrac{9}{4}−49 ab5
2a3 - 3a2b and −12-\dfrac{1}{2}−21 ab2
