Multiply :
−23-\dfrac{2}{3}−32 a7b2 and −94-\dfrac{9}{4}−49 ab5
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−23a7b2×(−94ab5)=2×93×4a7+1b2+5=1812a8b7=32a8b7-\dfrac{2}{3}a^7b^2 \times \Big(-\dfrac{9}{4}ab^5\Big)\\[1em] = \dfrac{2 \times 9}{3 \times 4}a^{7 + 1}b^{2+5}\\[1em] = \dfrac{18}{12}a^8b^7\\[1em] = \dfrac{3}{2}a^8b^7\\[1em]−32a7b2×(−49ab5)=3×42×9a7+1b2+5=1218a8b7=23a8b7
Hence, - 23\dfrac{2}{3}32 a7b2 x - 94\dfrac{9}{4}49 ab5 = 32\dfrac{3}{2}23 a8b7
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