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Mathematics

Multiply :

23-\dfrac{2}{3} a7b2 and 94-\dfrac{9}{4} ab5

Algebraic Expressions

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Answer

23a7b2×(94ab5)=2×93×4a7+1b2+5=1812a8b7=32a8b7-\dfrac{2}{3}a^7b^2 \times \Big(-\dfrac{9}{4}ab^5\Big)\\[1em] = \dfrac{2 \times 9}{3 \times 4}a^{7 + 1}b^{2+5}\\[1em] = \dfrac{18}{12}a^8b^7\\[1em] = \dfrac{3}{2}a^8b^7\\[1em]

Hence, - 23\dfrac{2}{3} a7b2 x - 94\dfrac{9}{4} ab5 = 32\dfrac{3}{2} a8b7

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