Name the products formed and write an equation when ethyne is added to the following in an inert solvent:

(a) chlorine

(b) bromine

(c) iodine

(d) hydrogen

(e) excess of hydrochloric acid.

1,2-dichloro ethene and 1,1,2,2 -tetrachloro ethane will be formed.

C₂H₂ + Cl₂ ⟶ C₂H₂Cl₂ + Cl₂ ⟶ C₂H₂Cl₄

(b) Bromine

1,2-dibromo ethene and 1,1,2,2 -tetrabromo ethane will be formed.

C₂H₂ + Br₂ ⟶ C₂H₂Br₂ + Br₂ ⟶ C₂H₂Br₄

(c) Iodine

1,2-di-iodoethene will be formed.

C₂H₂ + I₂ ⟶ ICH=CHI

(d) Hydrogen

Ethene and then ethane will be formed.

$\underset{\text{ Ethyne}}{\text{C}$2\text{H}2} + \text{H}2 \xrightarrow{\text{Nickle}} \underset{\text{ethene}}{\text{C}2\text{H}4} + \text{H}2 \xrightarrow{\text{Nickle}} \underset{\text{ethane}}{\text{C}2\text{H}6}

(e) Excess of hydrochloric acid.

Chloro ethene and then 1,1-dichloro ethane will be formed.

$\underset{\text{ Ethyne}}{\text{C}$2\text{H}2} \xrightarrow{\text{+ HCl}} \underset{\text{chloro ethene}}{\text{C}2\text{H}3\text{Cl}} \xrightarrow{\text{+ HCl}} \underset{\text{1,1-dichloro ethane}}{\text{C}2\text{H}4\text{Cl}_2}