In the nuclear decay given below :

_ZX^A ⟶ _Z+1Y^A ⟶ _Z-1B^A-4 ⟶ _Z-1B^A-4

The particles emitted in the sequence are :

1. α, β, γ
2. β, α, γ
3. γ, β, α
4. β, γ, α

β, α, γ

Reason —

• In the first step, the atomic number increases from Z to Z + 1 while the mass number remains the same, which indicates β decay.

• In the second step, the atomic number decreases from Z+1 to Z−1 and the mass number decreases by 4, which corresponds to α decay.

• The final step shows no change in either atomic or mass number, indicating emission of γ radiation.

Therefore, the sequence of emitted particles is β, α, γ.