One tap can fill a cistern in 3 hours and the waste pipe can empty the full cistern in 5 hours. In what time will the empty cistern be full, if the tap and the waste pipe are kept open together?
Direct & Inverse Variations
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Question

One tap can fill a cistern in 3 hours and the waste pipe can empty the full cistern in 5 hours. In what time will the empty cistern be full, if the tap and the waste pipe are kept open together?

KnowledgeBoat · Accepted Answer

Tap's 1 hour work = Waste tap's 1 hour work = Both tap's 1 hour work = = = Total time taken by both pipe = hours Hence, with both taps kept open, the empty cistern will be full in hours.

Mathematics

One tap can fill a cistern in 3 hours and the waste pipe can empty the full cistern in 5 hours. In what time will the empty cistern be full, if the tap and the waste pipe are kept open together?

Direct & Inverse Variations

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Mathematics

One tap can fill a cistern in 3 hours and the waste pipe can empty the full cistern in 5 hours. In what time will the empty cistern be full, if the tap and the waste pipe are kept open together?

Direct & Inverse Variations

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is:
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