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Mathematics

A can do 14\dfrac{1}{4} of a work in 5 days and B can do 13\dfrac{1}{3} of the same work in 10 days. Find the number of days in which both working together will complete the work.

Direct & Inverse Variations

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Answer

A's 5 days work = 14\dfrac{1}{4}

A's 1 day work = 14×5\dfrac{1}{4 \times 5}

= 120\dfrac{1}{20}

B's 10 days work = 13\dfrac{1}{3}

B's 1 day work = 13×10\dfrac{1}{3 \times 10}

= 130\dfrac{1}{30}

(A + B)'s 1 day work = 120+130\dfrac{1}{20} + \dfrac{1}{30}

= (3+2)60\dfrac{(3 + 2)}{60}

= 560\dfrac{5}{60}

= 112\dfrac{1}{12}

A and B can do the work in 121\dfrac{12}{1} days

Hence, A and B working together can complete the work in 12 days.

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