Mathematics
A parallelogram ABCD and a trapezium EFCD have the same base DC and are between the same parallels l and m. If the length of AB > length of EF, then compare the areas of ABCD and EFCD.
Theorems on Area
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Answer
Let distance between lines l and m be h units.
We know that,
Area of parallelogram ABCD = base × height = DC × h
The length EF is less than AB (which is equal to DC). Since the average of DC and EF is smaller than DC itself, thus the parallelogram has a larger area.
ar(ABCD) > ar(EFCD).
Hence, ar(ABCD) > ar(EFCD).
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