Abscissa of a point is the solution of equation 3x - 2 = 7 and its ordinate is the solution of equation 8 - 3y = 2. The point is :

1. (3, 2)

2. (-3, 2)

3. (3, -2)

4. (-3, -4)

For each equation given below; name the dependent and independent variables.

(i) $y = \dfrac{4}{3}x - 7$

(ii) x = 9y + 4

(iii) $x = \dfrac{5y + 3}{2}$

(iv) $y = \dfrac{1}{7}(6x + 5)$

Find the values of x and y if :

(i) (x - 1, y + 3) = (4, 4)

(ii) (3x + 1, 2y - 7) = (9, - 9)

(iii) (5x - 3y, y - 3x) = (4, - 4)

Use the graph given below, to find the co-ordinates of the point (s) satisfying the given conditions :

(i) the abscissa is 2.

(ii) the ordinate is 0.

(iii) the ordinate is 3.

(iv) the ordinate is - 4.

(v) the abscissa is 5.

(vi) the abscissa is equal to the ordinate.

(vii) the ordinate is half of the abscissa.