Mathematics
Prove that a triangle ABC is isosceles, if :
(i) altitude AD bisects angle BAC or,
(ii) bisector of angle BAC is perpendicular to base BC.
Triangles
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Answer
Let AD be the altitude on side BC.

We know that,
Altitude from a point is always perpendicular to other side.
Let altitude AD bisect angle BAC.
Hence, segment AD satisfies both the conditions.
In △ ADB and △ ADC,
⇒ AD = AD (Common side)
⇒ ∠BAD = ∠CAD (Since, AD bisects angle BAC)
⇒ ∠ADB = ∠ADC (Since, AD is altitude to side BC)
∴ Δ ADB ≅ Δ ADC (By A.S.A. axiom)
We know that,
Corresponding parts of congruent triangle are equal.
⇒ AB = AC.
Hence, proved that ABC is an isosceles triangle.
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