Assertion (A): In the given figure, S is any point on side QR.

∴ PQ + QR + RP > 2PS

Reason (R): In ΔPQS, PQ + QS > PS and in ΔPRS, PR + SR > PS

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true and R is the correct reason for A.

4. Both A and R are true and R is the incorrect reason for A.

In △ PQS,

⇒ PQ + QS > PS ……(1) [Sum of any two sides of a triangle is greater than the third side]

In △ PRS,

⇒ RP + RS > PS ……(2) [Sum of any two sides of a triangle is greater than the third side]

So, reason (R) is true.

Adding equations (1) and (2), we get :

⇒ PQ + QS + RP + RS > PS + PS

⇒ PQ + (QS + RS) + RP > 2PS

⇒ PQ + QR + RP > 2PS.

So, assertion (A) is true.

∴ Both A and R are true, and R is the correct reason for A.

Hence, option 3 is the correct option.