Mathematics

Prove that :
If a log b + b log a - 1 = 0, then b^a.a^b = 10

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Given,

⇒ a log b + b log a - 1 = 0

⇒ log b^a + log a^b = 1

⇒ log b^a + log a^b = log 10

⇒ log b^a.a^b = log 10

⇒ b^a.a^b = 10.

Hence, proved that b^a.a^b = 10.

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