Mathematics
The quadratic equation x2 + x + p = 0 has real and distinct roots, find the value of p.
Quadratic Equations
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Answer
Comparing equation x2 + x + p = 0, with ax2 + bx + c = 0, we get :
a = 1, b = 1 and c = p.
Since, equation has real and distinct roots.
∴ D > 0
⇒ b2 - 4ac > 0
⇒ 12 - 4 × 1 × p > 0
⇒ 1 - 4p > 0
⇒ 4p < 1
⇒ p < .
Hence, p < .
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