For real roots of a quadratic equation, the discriminant must be:
greater than or equal to zero
greater than zero
less than or equal to zero
less than zero

Question

For real roots of a quadratic equation, the discriminant must be: 1. greater than or equal to zero 2. greater than zero 3. less than or equal to zero 4. less than zero

KnowledgeBoat · Accepted Answer

If the Discriminant is greater than 0, then the roots are real and distinct.

If the Discriminant is equal to 0, then the roots are real and equal.

Thus, for real roots of a quadratic equation, the discriminant must be greater than or equal to zero.

Hence, option 1 is the correct option.

Mathematics

For real roots of a quadratic equation, the discriminant must be:
greater than or equal to zero
greater than zero
less than or equal to zero
less than zero

Quadratic Equations

Answer

Related Questions

The roots of the equation px² + qx + r = 0, where p ≠ 0, are given by:
$x = \dfrac{-p \pm \sqrt{q^{2} - 4pr}}{2p}$
$x = \dfrac{-q \pm \sqrt{q^{2} - 2pr}}{4p}$
$x = \dfrac{-q \pm \sqrt{q^{2} - 4pr}}{2p}$
$x = \dfrac{-q \pm \sqrt{q^{2} - 4pr}}{2q}$

The discriminant of the quadratic equation ax² + bx + c = 0, a ≠ 0 is given by:
b² - 2ac
b² - ac
b² - 4ac
none of these

The roots of the quadratic equation px² - qx + r = 0 are real and equal if :
(a) p² = 4qr
(b) q² = 4pr
(c) –q² = 4pr
(d) p² > 4qr

If the roots of the quadratic equation, ax² + bx + c = 0, a ≠ 0 are real and equal, then each root is equal to:
$\dfrac{-a}{2b}$
$\dfrac{-b}{2a}$
$\dfrac{-2a}{b}$
$\dfrac{-c}{2a}$

Mathematics

For real roots of a quadratic equation, the discriminant must be:greater than or equal to zerogreater than zeroless than or equal to zeroless than zero

Quadratic Equations

Answer

Related Questions

The discriminant of the quadratic equation ax2 + bx + c = 0, a ≠ 0 is given by:b2 - 2acb2 - acb2 - 4acnone of these

The roots of the quadratic equation px2 - qx + r = 0 are real and equal if :(a) p2 = 4qr(b) q2 = 4pr(c) –q2 = 4pr(d) p2 > 4qr

If the roots of the quadratic equation, ax2 + bx + c = 0, a ≠ 0 are real and equal, then each root is equal to:−a2b\dfrac{-a}{2b}2b−a​−b2a\dfrac{-b}{2a}2a−b​−2ab\dfrac{-2a}{b}b−2a​−c2a\dfrac{-c}{2a}2a−c​

For real roots of a quadratic equation, the discriminant must be:
greater than or equal to zero
greater than zero
less than or equal to zero
less than zero

The discriminant of the quadratic equation ax² + bx + c = 0, a ≠ 0 is given by:
b² - 2ac
b² - ac
b² - 4ac
none of these

The roots of the quadratic equation px² - qx + r = 0 are real and equal if :
(a) p² = 4qr
(b) q² = 4pr
(c) –q² = 4pr
(d) p² > 4qr

If the roots of the quadratic equation, ax² + bx + c = 0, a ≠ 0 are real and equal, then each root is equal to:
$\dfrac{-a}{2b}$
$\dfrac{-b}{2a}$
$\dfrac{-2a}{b}$
$\dfrac{-c}{2a}$