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Physics

(a) Refractive index of glass with respect to water is 98\dfrac{9}{8}. Find the refractive index of water with respect to glass.

(b) Name the principle used to find the value in part (a).

(c) If we change the temperature of water,then will the ratio 98\dfrac{9}{8} remain the same? Write yes or no.

Refraction Plane Surfaces

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Answer

(a) Given,

Refractive index of glass with respect to water = 98\dfrac{9}{8}

Then, according to the principle of reversibility of light

Refractive index of water with respect to glass =
1Refractive index of glass w.r.t water=198=89\dfrac{1}{\text {Refractive index of glass w.r.t water}} = \dfrac{1}{\dfrac{9}{8}}=\dfrac{8}{9}

(b) Principle of reversibility of light

(c) If temperature is changed of water then the ratio 98\dfrac{9}{8} will also change as refractive index of medium is inversely proportional to the temperature i.e., on increasing temperature refractive index of a medium decreases and vice versa.

So, If we change the temperature of water,then the ratio 98\dfrac{9}{8} will not remain the same.

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