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Physics

Light travels a distance of ‘10x’ units in time ‘t1’ in vacuum and it travels a distance of ‘x’ units in time ‘t2’ in a denser medium. Using this information answer the question that follows :

(a) ‘Light covers a distance of ‘20x’ units in time ‘t1’ in diamond.’ State true or false.

(b) Calculate the refractive index of the medium in terms of ‘t1’ and ‘t2’.

Refraction Plane Surfaces

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Answer

(a) False because speed of light in vacuum is highest and diamond is a denser medium so speed of light will be lower and hence, it can not travel a distance 20x in diamond which is two times of distance travelled by light in vacuum.

(b) Given,

Distance travelled by light in vacuum = 10x

Time taken by light in vacuum = t1

Distance travelled by light in the medium = x

Time taken by light in diamond = t2

As,

Speed of light in vacuum (c)=Distance travelled by light in vacuumTime taken by light in vacuum=10xt1\text {Speed of light in vacuum (c)} = \dfrac {\text {Distance travelled by light in vacuum}}{\text {Time taken by light in vacuum}}= \dfrac {10\text x}{\text t_1}

and

Speed of light in diamond (v)=Distance travelled by light in diamondTime taken by light in diamond=xt2\text {Speed of light in diamond (v)} = \dfrac {\text {Distance travelled by light in diamond}}{\text {Time taken by light in diamond}}= \dfrac {\text x}{\text t_2}

then,

The refractive index of diamond=Speed of light in vacuum (c)speed of light in diamond (v)=10xt1xt2=10t2t1\text {The refractive index of diamond} = \dfrac{\text{Speed of light in vacuum (c)}}{\text {speed of light in diamond (v)}}= \dfrac{\dfrac {10\text x}{\text t1}}{\dfrac {\text x}{\text t2}} \\[1em] =\dfrac{10 \text t2}{\text t1}

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