Mathematics
The runs scored by a cricketer in last 20 innings are given below.
| 32 | 17 | 0 | 61 | 17 | 32 | 5 | 17 | 70 | 61 |
| 5 | 17 | 32 | 61 | 5 | 17 | 32 | 70 | 32 | 17 |
The mean runs of the cricketer per inning is :
21
24
29
30
Statistics
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Answer
Total innings = 20
Arranging the table into Runs and frequency :
| Runs | Frequency |
|---|---|
| 0 | 1 |
| 5 | 3 |
| 17 | 6 |
| 32 | 5 |
| 61 | 3 |
| 70 | 2 |
0 × 1 = 0
5 × 3 = 15
17 × 6 = 102
32 × 5 = 160
61 × 3 = 183
70 × 2 = 140
⇒ Total runs = 0 + 15 + 102 + 160 + 183 + 140 = 600
⇒ Mean =
= = 30.
Hence, option 4 is the correct option.
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Related Questions
The median of the following observations : 11, 12, 14, 18, (x + 4), 30, 32, 35, 41 arranged in ascending order is 24. The value of x is :
19
20
21
21.5
If the mean of x - 3, x - 1, 7, x, 2x - 1 and 3x - 5 is 3.5, then the median is :
2.5
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3.8
3.9
Case Study:
A school organized a Health Check Up Camp for its students. The weights (in kg) of the students of a class were recorded as below :41, 40, 36, 52, 50, 48, 47, 45,
40, 41, 42, 49, 50, 51, 38, 41,
40, 45, 40, 39, 49, 51, 48, 46,
44, 50, 57, 38, 41, 51Based on the above information, answer the following questions:
The range of the data is :
(a) 20 kg
(b) 21 kg
(c) 22 kg
(d) 23 kgMean weight of the data is :
(a) 45 kg
(b) 44.5 kg
(c) 42.5 kg
(d) 40.5 kgMedian of the data is :
(a) 44 kg
(b) 45 kg
(c) 45.5 kg
(d) 46 kgOne student weighing 45 kg, was absent on that day. Next day, the teacher added his name in the list. The average weight of the new group is :
(a) 47 kg
(b) 46.4 kg
(c) 46 kg
(d) 45 kgThe median weight of the students after adding the absentee in the list is :
(a) 45 kg
(b) 46 kg
(c) 44.5 kg
(d) 44.2 kg
Assertion (A) : The mean of 19 numbers is 38. If the mean of the first 10 numbers is 36 and that of the last 10 is 40, then the 10th number is 38.
Reason (R) : Mean =
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false