Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of (i) 9 Ω, (ii) 4 Ω.

If we connect resistors in series, R = 6 Ω + 6 Ω + 6 Ω = 18 Ω. If we connect all resistors in parallel, Hence, R = 2Ω We can obtain the desired value by connecting two of the resistors in either series or parallel. Case (i) If two resistors are connected in parallel, then their equivalent resistance is Hence, R p = 3Ω The third resistor in series, then we get equivalent resistance R p + 6 = 3 + 6 = 9Ω ∴ To get a resistance of 9 Ω, two 6 Ω resistors should be connected in parallel and the third 6 Ω resistor should be connected in series with the combination as shown below: Case (ii) When two resistors are connected in series, their equivalent resistance is R s = 6 Ω + 6 Ω = 12 Ω The third resistor is connected in parallel with 12 Ω. Hence the equivalent resistance is: ⇒ R = 4 Ω ∴ To get a resistance of 4 Ω, two 6 Ω resistors should be connected in series and the third 6 Ω resistor should be connected in parallel with the combination as shown below:

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Science

Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of (i) 9 Ω, (ii) 4 Ω.

Current Electricity

Related Questions

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