Show that one root of the quadratic equation x 2 + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.

Substituting x = -3 in x 2 + (3 - 2a)x - 6a = 0, ⇒ (-3) 2 + (3 - 2a)(-3) - 6a = 0 ⇒ 9 - 9 + 6a - 6a = 0 ⇒ 0 = 0. Hence, -3 is one root of the quadratic equation. We know that, x = Hence, the other root is 2a.