Show that one root of the quadratic equation x² + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.
Quadratic Equations
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Question

Show that one root of the quadratic equation x² + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.

KnowledgeBoat · Accepted Answer

Substituting x = -3 in x² + (3 - 2a)x - 6a = 0, ⇒ (-3)² + (3 - 2a)(-3) - 6a = 0 ⇒ 9 - 9 + 6a - 6a = 0 ⇒ 0 = 0. Hence, -3 is one root of the quadratic equation. We know that, x = Hence, the other root is 2a.

Mathematics

Show that one root of the quadratic equation x² + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.

Quadratic Equations

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Mathematics

Show that one root of the quadratic equation x2 + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.

Quadratic Equations

Related Questions

Find the solution of the quadratic equation 2x2 - mx - 25n = 0; if m + 5 = 0 and n - 1 = 0.

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Show that one root of the quadratic equation x² + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.

Find the solution of the quadratic equation 2x² - mx - 25n = 0; if m + 5 = 0 and n - 1 = 0.

Solve :
(a + b)²x² - (a + b)x - 6 = 0; a + b ≠ 0.