Mathematics
Find the solution of the quadratic equation 2x2 - mx - 25n = 0; if m + 5 = 0 and n - 1 = 0.
Quadratic Equations
15 Likes
Answer
Given, m + 5 = 0 and n - 1 = 0
∴ m = -5 and n = 1.
Substituting values of m and n in 2x2 - mx - 25n = 0 we get,
⇒ 2x2 - (-5)x - 25(1) = 0
⇒ 2x2 + 5x - 25 = 0
⇒ 2x2 + 10x - 5x - 25 = 0
⇒ 2x(x + 5) - 5(x + 5) = 0
⇒ (2x - 5)(x + 5) = 0
⇒ (2x - 5) = 0 or x + 5 = 0
⇒ x = or x = -5.
Hence, x = or -5.
Answered By
6 Likes
Related Questions
One root of the quadratic equation 8x2 + mx + 15 = 0 is . Find the value of m. Also, find other root of equation.
Show that one root of the quadratic equation x2 + (3 - 2a)x - 6a = 0 is -3. Hence, find its other root.
Solve :
(a + b)2x2 - (a + b)x - 6 = 0; a + b ≠ 0.
Without solving the following quadratic equation, find the value of 'm' for which the given equation has real and equal roots.
x2 + 2(m - 1)x + (m + 5) = 0