Without solving the following quadratic equation, find the value of 'm' for which the given equation has real and equal roots.

x² + 2(m - 1)x + (m + 5) = 0

Since, equation has equal roots, D = 0.

∴ b² - 4ac = 0

⇒ (2(m - 1))² - 4(1)(m + 5) = 0

⇒ (2m - 2)² - (4m + 20) = 0

⇒ 4m² + 4 - 8m - 4m - 20 = 0

⇒ 4m² - 12m - 16 = 0

⇒ 4(m² - 3m - 4) = 0

⇒ m² - 3m - 4 = 0

⇒ m² - 4m + m - 4 = 0

⇒ m(m - 4) + 1(m - 4) = 0

⇒ (m + 1)(m - 4) = 0

⇒ m + 1 = 0 or m - 4 = 0

⇒ m = -1 or m = 4.

Hence, m = -1, 4.