Simplify:
843+2532−(127)−238^{\dfrac{4}{3}} + 25^{\dfrac{3}{2}} - \Big(\dfrac{1}{27}\Big)^{-\dfrac{2}{3}}834+2523−(271)−32
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843+2532−(127)−23=(23)43+(52)32−(1333)−23=(2)3×43+(5)2×32−(13)−3×23=(2)4+(5)3−(13)−2=(2)4+(5)3−(31)2=16+125−9=1328^{\dfrac{4}{3}} + 25^{\dfrac{3}{2}} - \Big(\dfrac{1}{27}\Big)^{-\dfrac{2}{3}}\\[1em] = (2^3)^{\dfrac{4}{3}} + (5^2)^{\dfrac{3}{2}} - \Big(\dfrac{1^3}{3^3}\Big)^{-\dfrac{2}{3}}\\[1em] = (2)^{3\times\dfrac{4}{3}} + (5)^{2\times\dfrac{3}{2}} - \Big(\dfrac{1}{3}\Big)^{-3\times\dfrac{2}{3}}\\[1em] = (2)^4 + (5)^3 - \Big(\dfrac{1}{3}\Big)^{-2}\\[1em] = (2)^4 + (5)^3 - \Big(\dfrac{3}{1}\Big)^2\\[1em] = 16 + 125 - 9\\[1em] = 132834+2523−(271)−32=(23)34+(52)23−(3313)−32=(2)3×34+(5)2×23−(31)−3×32=(2)4+(5)3−(31)−2=(2)4+(5)3−(13)2=16+125−9=132
843+2532−(127)−23=1328^{\dfrac{4}{3}} + 25^{\dfrac{3}{2}} - \Big(\dfrac{1}{27}\Big)^{-\dfrac{2}{3}} = 132834+2523−(271)−32=132
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Compute:
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(27)23÷(8116)−14(27)^{\dfrac{2}{3}} ÷ \Big(\dfrac{81}{16}\Big)^{-\dfrac{1}{4}}(27)32÷(1681)−41
[(64)−2]−3÷[{(−8)2}3]2[(64)^{-2}]^{-3} ÷ [{(-8)^2}^3]^2[(64)−2]−3÷[{(−8)2}3]2
(2−3−2−4)(2−3+2−4)(2^{-3} - 2^{-4})(2^{-3} + 2^{-4})(2−3−2−4)(2−3+2−4)
