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Mathematics

Simplify:

(x20y10z55)÷x3y3(\sqrt[5]{x^{20}y^{-10}z^5}) ÷ \dfrac{x^3}{y^3}

Exponents

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Answer

(x20y10z55)÷x3y3=(x205y105z55)÷x3y3=(x4y2z1)÷x3y3=(x4y2z1)×y3x3=(x43y2+3z)=(x1y1z)=xyz(\sqrt[5]{x^{20}y^{-10}z^5}) ÷ \dfrac{x^3}{y^3}\\[1em] = (x^{\dfrac{20}{5}}y^{\dfrac{-10}{5}}z^{\dfrac{5}{5}}) ÷ \dfrac{x^3}{y^3}\\[1em] = (x^4y^{-2}z^1) ÷ \dfrac{x^3}{y^3}\\[1em] = (x^4y^{-2}z^1) \times \dfrac{y^3}{x^3}\\[1em] = (x^{4-3}y^{-2+3}z)\\[1em] = (x^1y^1z)\\[1em] = xyz

(x20y10z55)÷x3y3=xyz(\sqrt[5]{x^{20}y^{-10}z^5}) ÷ \dfrac{x^3}{y^3} = xyz

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