Simplify and express as positive indices:
(a−2b)−2.(ab)−3(a^{-2}b)^{-2}.(ab)^{-3}(a−2b)−2.(ab)−3
6 Likes
(a−2b)−2.(ab)−3=(a−2×(−2)b−2).(a−3b−3)=(a4b−2).(a−3b−3)=(a4+(−3)b−2+(−3))=(a4−3b−2−3)=(a1b−5)(a^{-2}b)^{-2}.(ab)^{-3}\\[1em] = (a^{-2\times(-2)}b^{-2}).(a^{-3}b^{-3})\\[1em] = (a^{4}b^{-2}).(a^{-3}b^{-3})\\[1em] = (a^{4+(-3)}b^{-2+(-3)})\\[1em] = (a^{4-3}b^{-2-3})\\[1em] = (a^{1}b^{-5})(a−2b)−2.(ab)−3=(a−2×(−2)b−2).(a−3b−3)=(a4b−2).(a−3b−3)=(a4+(−3)b−2+(−3))=(a4−3b−2−3)=(a1b−5)
(a−2b)−2.(ab)−3=(a1b−5)=ab5(a^{-2}b)^{-2}.(ab)^{-3} = (a^{1}b^{-5}) = \dfrac{a}{b^5}(a−2b)−2.(ab)−3=(a1b−5)=b5a
Answered By
3 Likes
Simplify:
(x20y−10z55)÷x3y3(\sqrt[5]{x^{20}y^{-10}z^5}) ÷ \dfrac{x^3}{y^3}(5x20y−10z5)÷y3x3
[256a1681b4]−34\Big[\dfrac{256a^{16}}{81b^4}\Big]^{\dfrac{-3}{4}}[81b4256a16]4−3
(xny−m)4×(x3y−2)−n(x^ny^{-m})^4\times(x^3y^{-2})^{-n}(xny−m)4×(x3y−2)−n
[125a−3y6]−13\Big[\dfrac{125a^{-3}}{y^6}\Big]^{\dfrac{-1}{3}}[y6125a−3]3−1
