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Mathematics

Simplify and express as positive indices:

(xnym)4×(x3y2)n(x^ny^{-m})^4\times(x^3y^{-2})^{-n}

Exponents

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Answer

(xnym)4×(x3y2)n=(xnym)4×(x3y2)n=(x4ny4m)×(x3ny2n)=(x4n3ny4m+2n)=(xny4my2n)=(xny2ny4m)(x^ny^{-m})^4\times(x^3y^{-2})^{-n}\\[1em] = (x^ny^{-m})^4\times(x^3y^{-2})^{-n}\\[1em] = (x^{4n}y^{-4m})\times(x^{-3n}y^{2n})\\[1em] = (x^{4n-3n}y^{-4m+2n})\\[1em] = (x^{n}y^{-4m}y^{2n})\\[1em] = (\dfrac{x^{n}y^{2n}}{y^{4m}})

(xnym)4×(x3y2)n=(xny2ny4m)(x^ny^{-m})^4\times(x^3y^{-2})^{-n} = (\dfrac{x^{n}y^{2n}}{y^{4m}})

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