Simplify:
(125x−3)13(125x^{-3})^{\dfrac{1}{3}}(125x−3)31
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(125x−3)13=(125x3)13=(53x3)13=(5x)3×13=(5x)33=5x=5x−1(125x^{-3})^{\dfrac{1}{3}}\\[1em] = \Big(\dfrac{125}{x^3}\Big)^{\dfrac{1}{3}}\\[1em] = \Big(\dfrac{5^3}{x^3}\Big)^{\dfrac{1}{3}}\\[1em] = \Big(\dfrac{5}{x}\Big)^{3 \times \dfrac{1}{3}}\\[1em] = \Big(\dfrac{5}{x}\Big)^{\dfrac{3}{3}}\\[1em] = \dfrac{5}{x} = 5x^{-1}(125x−3)31=(x3125)31=(x353)31=(x5)3×31=(x5)33=x5=5x−1
(125x−3)13=5x−1(125x^{-3})^{\dfrac{1}{3}} = 5x^{-1}(125x−3)31=5x−1
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