Simplify:
x2n+7.(x2)3n+2x4(2n+3)\dfrac{x^{2n+7}.(x^2)^{3n+2}}{x^{4(2n+3)}}x4(2n+3)x2n+7.(x2)3n+2
5 Likes
x2n+7.(x2)3n+2x4(2n+3)=x2n+7.x2(3n+2)x4(2n+3)=x2n+7.x6n+4x8n+12=x(2n+7)+(6n+4)x8n+12=x2n+7+6n+4x8n+12=x8n+11x8n+12=x(8n+11)−(8n+12)=x8n+11−8n−12=x−1=1x\dfrac{x^{2n+7}.(x^2)^{3n+2}}{x^{4(2n+3)}}\\[1em] = \dfrac{x^{2n+7}.x^{2(3n+2)}}{x^{4(2n+3)}}\\[1em] = \dfrac{x^{2n+7}.x^{6n+4}}{x^{8n+12}}\\[1em] = \dfrac{x^{(2n+7)+(6n+4)}}{x^{8n+12}}\\[1em] = \dfrac{x^{2n+7+6n+4}}{x^{8n+12}}\\[1em] = \dfrac{x^{8n+11}}{x^{8n+12}}\\[1em] = x^{(8n+11)-(8n+12)}\\[1em] = x^{8n+11-8n-12}\\[1em] = x^{-1}\\[1em] = \dfrac{1}{x}x4(2n+3)x2n+7.(x2)3n+2=x4(2n+3)x2n+7.x2(3n+2)=x8n+12x2n+7.x6n+4=x8n+12x(2n+7)+(6n+4)=x8n+12x2n+7+6n+4=x8n+12x8n+11=x(8n+11)−(8n+12)=x8n+11−8n−12=x−1=x1
x2n+7.(x2)3n+2x4(2n+3)=1x\dfrac{x^{2n+7}.(x^2)^{3n+2}}{x^{4(2n+3)}} = \dfrac{1}{x}x4(2n+3)x2n+7.(x2)3n+2=x1
Answered By
4 Likes
Find the value of n, when:
a2n−3×(a2)n+1(a4)−3=(a3)3÷(a6)−3\dfrac{a^{2n-3}\times(a^2)^{n+1}}{(a^4)^{-3}} = (a^3)^3 ÷ (a^6)^{-3}(a4)−3a2n−3×(a2)n+1=(a3)3÷(a6)−3
a2n+3.a(2n+1)(n+2)(a3)2n+1.an(2n+1)\dfrac{a^{2n+3}.a^{(2n+1)(n+2)}}{(a^3)^{2n+1}.a^{n(2n+1)}}(a3)2n+1.an(2n+1)a2n+3.a(2n+1)(n+2)
Evaluate:
(2−3+3−2)×70(2^{-3} + 3^{-2})\times 7^0(2−3+3−2)×70
(80+2−1)×32(8^0 + 2^{-1})\times 3^2(80+2−1)×32
