Simplify the following expression:(3+√3)(2+√2)

= 3 x 2 + 3 x + 2 x + x = 6 + 3 + 2 + Hence,

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Mathematics

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$(3 + \sqrt{3}) (2 + \sqrt{2})$

= 3 x 2 + 3 x $\sqrt{2}$ + 2 x $\sqrt{3}$ + $\sqrt{3}$ x $\sqrt{2}$

= 6 + 3 $\sqrt{2}$ + 2 $\sqrt{3}$ + $\sqrt{6}$

Hence, $(3 + \sqrt{3}) (2 + \sqrt{2}) = 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}$

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