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Mathematics

Classify the following numbers as rational or irrational:

(i) 2 − 5\sqrt{5}

(ii) 3 + 23\sqrt{23}23\sqrt{23}

(iii) 2777\dfrac{2\sqrt{7}}{7\sqrt{7}}

(iv) 12\dfrac{1}{\sqrt{2}}

(v) 2π

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Answer

(i) 2 − 5\sqrt{5}

If in any rational number we add, subtract, multiply or divide any irrational number it becomes irrational number.

Hence, 2 − (5)\sqrt{5}) is an irrational number.

(ii) 3 + 23\sqrt{23}23\sqrt{23}

= 3 + 23\sqrt{23}23\sqrt{23}

= 3

Hence, (3 + 23\sqrt{23}) − 23\sqrt{23} is a rational number

(iii) 2777\dfrac{2\sqrt{7}}{7\sqrt{7}}

2777\dfrac{2\sqrt{7}}{7\sqrt{7}} = 27\dfrac{2}{7}

It is in pq\dfrac{p}{q} where q ≠ 0.

Hence, is a rational number

(iv) 12\dfrac{1}{\sqrt{2}}

12=rationalirrational\dfrac{1}{\sqrt{2}} = \dfrac{\text{rational}}{\sqrt{\text{irrational}}} = irrational number

If in any rational number we add, subtract, multiply or divide any irrational number it becomes irrational

Hence, 12\dfrac{1}{\sqrt{2}} is an irrational number

(v) 2π

2 x π = irrational number [∵ rational x irrational number = irrational number]

Hence, 2π is an irrational number

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