If sin 3A = 1 and 0 ≤ A ≤ 90°, find : (i) sin A (ii) cos 2 A (iii) tan^2 A - 1/cos^2 A

Question

KnowledgeBoat · Accepted Answer

sin 3A = 1 ⇒ sin 3A = sin 90° So, 3A = 90° ⇒ A = (i) sin A = sin 30° = Hence, sin A = . (ii) cos 2 A = cos (2 x 30°) = cos 60° = Hence, cos 2A = . (iii) tan2 A - Hence, tan2 A - = -1.

Mathematics

If sin 3A = 1 and 0 ≤ A ≤ 90°, find : (i) sin A (ii) cos 2 A (iii) tan^2 A - 1/cos^2 A

Trigonometric Identities

Related Questions

If 4 sin² θ - 1 = 0 and angle θ is less than 90°, find the value of θ and hence the value of cos² θ + tan² θ.

Mathematics

If sin 3A = 1 and 0 ≤ A ≤ 90°, find : (i) sin A (ii) cos 2 A (iii) tan^2 A - 1/cos^2 A

Trigonometric Identities

Related Questions

If 4 sin2 θ - 1 = 0 and angle θ is less than 90°, find the value of θ and hence the value of cos2 θ + tan2 θ.

If 4 sin² θ - 1 = 0 and angle θ is less than 90°, find the value of θ and hence the value of cos² θ + tan² θ.