From a solid wooden cylinder of height 28 cm and diameter 6 cm, two conical cavities are hollowed out. The diameters of the cone are also of 6 cm and height 10.5 cm. Taking π = , find the volume of remaining solid.

Question

KnowledgeBoat · Accepted Answer

Given, Diameter of solid wooden cylinder (D) = 6 cm Radius of solid wooden cylinder (R) = cm = 3 cm Height of solid wooden cylinder (H) = 28 cm Diameter of cone (d) = 6 cm Radius of cone (r) = cm = 3 cm Height of cone (h) = 10.5 cm Volume of cylinder (V) = πr2h Volume of single cone (v) = πR2H Volume of two conical cavities = 2 x 99 = 198 cm2 Volume of remaining solid = Volume of cylinder - Volume of 2 conical cavities = 792 - 198 = 594 cm2. Hence, volume of remaining solid = 594 cm2.

Mathematics

From a solid wooden cylinder of height 28 cm and diameter 6 cm, two conical cavities are hollowed out. The diameters of the cone are also of 6 cm and height 10.5 cm. Taking π = , find the volume of remaining solid.

Mensuration

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