Solve the following equation using quadratic formula:

4 - 11x = 3x²

⇒ 3x² + 11x - 4 = 0

Comparing equation 3x² + 11x - 4 = 0 with ax² + bx + c = 0, we get :

a = 3, b = 11 and c = -4.

By formula,

x = $\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Substituting values we get :

$\Rightarrow x = \dfrac{-(11) \pm \sqrt{(11)^2 - 4 \times (3) \times (-4)}}{2(3)} \\[1em] = \dfrac{-11 \pm \sqrt{121 + 48}}{6} \\[1em] = \dfrac{-11 \pm \sqrt{169}}{6} \\[1em] = \dfrac{-11 \pm 13}{6} \\[1em] = \dfrac{-11 + 13}{6} \text{ or } \dfrac{-11 - 13}{6} \\[1em] = \dfrac{2}{6} \text{ or } \dfrac{-24}{6} \\[1em] = \dfrac{1}{3} \text{ or } -4.$

Hence, $x = \Big{\dfrac{1}{3}, -4\Big}$.