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Mathematics

Solve each of the following linear equations:

(i) x + 6 = 8

(ii) x − 2 = −5

(iii) 4x = 6

(iv) x2=5\dfrac{x}{2} = 5

(v) 2y − 3 = 2

(vi) 5y + 2 = 4

Simple Equations

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Answer

(i) Given x + 6 = 8

⇒ x = 8 − 6     [Transposing +6 to RHS]

∴ x = 2

(ii) Given x − 2 = −5

⇒ x = −5 + 2     [Transposing −2 to RHS]

∴ x = −3

(iii) Given 4x = 6

x=64x = \dfrac{6}{4}     [Dividing both sides by 4]

∴ x = 32\dfrac{3}{2}

(iv) Given x2=5\dfrac{x}{2} = 5

⇒ x = 5 × 2

∴ x = 10

(v) Given 2y − 3 = 2

⇒ 2y = 2 + 3     [Transposing −3 to RHS]

⇒ 2y = 5

y=52y = \dfrac{5}{2}     [Dividing both sides by 2]

∴ y = 52\dfrac{5}{2}

(vi) Given 5y + 2 = 4

⇒ 5y = 4 − 2     [Transposing +2 to RHS]

⇒ 5y = 2

y=25y = \dfrac{2}{5}     [Dividing both sides by 5]

y = 25\dfrac{2}{5}

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