Solve the following simultaneous equations: (a/x) - (b/y)=0, (ab^2)/x + (a^2b)/y = (a^2 + b^2)

Substituting in , ⇒ am - bn = 0 ⇒ am = bn ⇒ m = ........(1) Substituting in ⇒ ab2m + a2bn = a2 + b2 .........(2) Substituting value of m from equation (1) in (2), we get : ⇒ ab2 + a2bn = a2 + b2 ⇒ b3n + a2bn = a2 + b2 ⇒ bn(b2 + a2) = a2 + b2 ⇒ bn = ⇒ bn = 1 ⇒ n = Substituting value of n in equation (1), we get: ⇒ m = ⇒ m = Hence, x = a, y = b.